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uri 1890 solution in cpp
by ujjal roy
#include<bits/stdc++.h>
using namespace std;
main()
{
long long int t,c,d,i,sum;
cin>>t;
while(t--)
{
cin>>c>>d;
if(c==0&&d==0) cout<<"0"<<endl;
else if(c==0&&d>0)
{
sum=pow(10,d);
cout<<sum<<endl;
}
else if(c>0&&d==0)
{
sum=pow(26,c);
cout<<sum<<endl;
}
else if(c>0&&d>0)
{
sum=1;
for(i=0;i<c;i++) sum=sum*26;
for(i=0;i<d;i++) sum=sum*10;
cout<<sum<<endl;
}
}
return 0;
}
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