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6.finding and printing cycle of undirected graph using dfs

 #include <bits/stdc++.h>

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
template <class type1>
#define ll long long int
#define endl "\n"
#define ordered_set tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update>
using ordered_multiset = tree <type1, null_type, less_equal <type1>, rb_tree_tag, tree_order_statistics_node_update>;
 //ordered_multiset <ll> kek;(declaration for multiorder set)
// ordered_set o_set;(declaration)
//kek.order_of_key(i);(strictly less then i for multi order set)
//o_set.order_of_key(5) ;(strictly less then i for multi order set)
#define yes cout << "YES\n"
#define no cout << "NO\n"
#define mod 1000000007
ll POW(ll a,ll b)
{   ll ans=1;
   while(b>0)
   {   if(b%2)ans=(ans*a)%mod;
       b/=2;
       a=(a*a)%mod;
   }
   return ans;
}
const ll N=100009;
vector<ll>adj[N];
ll vis[N];
ll parent[N];
ll start,end1;
bool dfs(ll node,ll par)
{
    vis[node]=1;
    parent[node]=par;
    for(auto u:adj[node])
    {
         if(u==par)continue;
         if(vis[u])
         {
             start=u;
             end1=node;
            return true;
         }
         if(dfs(u,node))return true;
    }
    return false;
}
int main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
   
   ll n,m,i,j;
   cin>>n>>m;
   for(i=0;i<m;i++)
   {
      ll u,v;
      cin>>u>>v;
      adj[u].push_back(v);
      adj[v].push_back(u);
   }
   ll ans=0;
   for(i=1;i<=n;i++)
   {
     if(vis[i]==0)
     {
          if(dfs(i,-1))
          {
             ans=1;
             break;
          }
     }
   }
   if(ans)
   {
       vector<ll>v;
       v.push_back(start);
       v.push_back(end1);
       while(parent[end1]!=start)
       {
          end1=parent[end1];
          v.push_back(end1);
       }
       v.push_back(start);
       cout<<v.size()<<endl;
       for(auto u:v)cout<<u<<" ";
       cout<<endl;

   }
   else
   {
     cout<<"IMPOSSIBLE\n";
   }

    return 0;
}

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